In fig. if aob 125° then cod is equal to
WebFeb 8, 2024 · Answer: (D) 55°. Explanation: Since, quadrilateral circumscribing a circle subtends supplementary angles at the centre of the circle. ∴∠AOB + ∠COD = 180°. 125° + ∠COD = 180°. ∠COD = 180° – 125° = 55°. Question 3. In the given figure, AB is a chord of the circle and AOC is its diameter, such that ∠ACB = 50°. WebFeb 3, 2024 · In Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° ... In Fig., rays OA, OB, OC, OD and OE have the common endpoint, O. Show, that ∠AOB +∠BOC +∠COD +∠DOE + ∠EOA = 360°. asked Apr 17, 2024 in Lines and Angles by Madhuwant (38.1k points) lines and angles;
In fig. if aob 125° then cod is equal to
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WebIn Figure, the quadrilateral ABCD circumscribes a circle with centre O. If ∠AOB= 115 o, then find ∠COD Medium Solution Verified by Toppr In the quadrilateral ABCD ∵∠AOB=∠COD (Vertically opposite angle) ∴∠COD=115 0 Was this answer helpful? 0 0 Similar questions ABCD is a cyclic quadrilateral inscribed in a circle with the centre O. WebQuestion: In figure, if AOB = 125, then COD is equal to (a) 62.5 (b) 45 (c) 35 (d) 55 Solution: (d)We know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle. i.e., $\quad \angle A O B+\angle C O D=180^{\circ}$ $\Rightarrow \quad \angle C O D=180^{\circ}-\angle A O B$ $=180^{\circ} …
WebJan 4, 2024 · Here is your answer: The quadrilateral angle's circle meet at the point of the supplementary angles and that is at the center. ABCD will meet at a point where it won't … WebIn figure, if ∠AOB=125∘. Then ∠ COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° Solution We know that, the opposite sides of a quadrilateral circumscribing a circle subtend …
WebAug 28, 2024 · selected Aug 29, 2024 by Shyam01. Best answer. (D) 55°. ABCD is a quadrilateral circumscribing the circle. We know that, the opposite sides of a quadrilateral … WebWe know that opposite sides of a quadrilateral circumscribing a circle subtend supplementary. angles at the centre. Quadrilateral ABCD circumscribe a circle with centre …
WebNov 9, 2024 · In Fig., if AOB = 125°, then COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° ... In figure, if AOB is a diameter and ∠ADC = 120°, then ∠CAB = 30°. asked Aug 20, 2024 in Circles by Dev01 (51.9k points) circles; class-9; 0 votes. 1 answer. If AOB is a diameter of a circle and C is a point on the circle, then AC^2 + BC^2 = AB^2.
Web(a) 65° (b) 60° (c) 50° (d) 40° Answer: (c) 50° Explanation: As per the given question: ∠ABC = 90° (angle in Semicircle is right angle) In ∆ACB ∠A + ∠B + ∠C = 180° ∠A = 180° – (90° + 50°) ∠A = 40° Or ∠OAB = 40° Therefore, ∠BAT = 90° – 40° = 50° 7. If TP and TQ are the two tangents to a circle with centre O so that ∠POQ = 110°, then ∠PTQ is equal to halo grunt food nippleWebIn figure, if ∠AOB = 125°, then ∠COD is equal to 55°. Explanation: As in the given figure ABCD is a quadrilateral circumscribing the circle and we know that, the opposite sides of a … halo grunt birthday party skull locationWebOct 13, 2024 · In the following figure (not to scale), at the centre O, if the chord AB subtends double the angle that is subtended by chord CD and the angle ∠AEB = 2 ∠AOB, then ∠COD is equal to: This question was previously asked in. halo grunt birthday party skullWebIn the given figure, if ∠AOD= 135∘ then ∠BOC is equal to (a) 25∘ (b) 45∘ (c) 52.5∘ (d) 62.5∘ Solution The correct option is (b): 45∘ We know that the sum of angles subtended by opposite sides of a quadrilateral having a circumscribed circle is 180 degrees ∠AOD+∠BOC = 180∘ ∠BOC= 180∘−135∘ = 45∘ Suggest Corrections 47 Similar questions Q. burkhart funeral home sandwich ilWebIn the given figure, If ∠AOB=125 0, then ∠COD is equal to : A 62.5 0 B 45 0 C 125 0 D 55 0 Medium Solution Verified by Toppr Correct option is D) The quadrilateral angle's circle meet at the point of the supplementary angles and that is at the center. halo grunt evolutionWebJun 15, 2024 · In the figure, if ∠AOB = 125°, then ∠COD is equal to [NCERT Exemplar] (a) 45° (b) 35° (c) 55° (d) 62\(\frac { 1 }{ 2 }\)° Solution: (c) We know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle. ∠AOB + ∠COD = 180° => ∠COD = 180° – ∠AOB = 180 ... burkhart funeral home talihinaWebIn Fig. 8.9, if ∠AOB = 125°, then ∠COD is equal toa)62.5°b)45°c)35°d)55°Correct answer is option 'D'. Can you explain this answer? Opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the center of the circle. ∠COD=180-125 ∠COD=55 ~_~ Upvote 11 Reply View courses related to this question burkhart funeral service talihina ok